零质量的的英文
发音:
"零质量的"怎么读用"零质量的"造句
英文翻译手机版
- zero mass
- "零"英文翻译 zero zero sign; nought
- "质量"英文翻译 mass
- "的"英文翻译 4次方是 The fourth power of 2 i ...
- "零质量粒子" 英文翻译 : mass zero particle
- "质量的" 英文翻译 : molar; qualitative
- "低质量的" 英文翻译 : debased; lowgrade; low-quality
- "定性的,质量的" 英文翻译 : qualitative
- "高质量的" 英文翻译 : fine; high grade; highclass; highquality; of high/good quality; sth. of good/high quality
- "质的,质量的" 英文翻译 : qualitative
- "质量的改进" 英文翻译 : improvement in quality
- "最高质量的" 英文翻译 : top-notch
- "高质量的报纸" 英文翻译 : quality paper
- "高质量的服务" 英文翻译 : quality service
- "高质量的旅游" 英文翻译 : quality staff quality tourism
- "高质量的职员" 英文翻译 : high calibre staff
- "质量,块,团,大量的" 英文翻译 : mass
- "质量的定性的" 英文翻译 : qualitative
- "质量的惯性矩" 英文翻译 : mass moment of inertia
- "重质量的市场" 英文翻译 : quality market
- "不计质量的力模型" 英文翻译 : mechanical model without mass
- "单位质量的含量" 英文翻译 : load per unit of mass
- "单位质量的作用力" 英文翻译 : mass power
- "但高质量的不多" 英文翻译 : cbn
- "对产品质量的责任" 英文翻译 : products liability
- "非缓冲质量的振动" 英文翻译 : secondary vibration
例句与用法
- According to goldstone theorem , the goldstone bosons with zero mass will emerge as the chiral symmetry is spontaneously broken
由goldstone理论可知,当手征自发破缺时会生成零质量的goldstone玻色子。 - In quantum chromodynamics ( qcd ) , vacuum is not trivial , that is , vacuum carry quantum numbers . such a behavior is embodied by non - perturbative con - densates of quarks and gluons . since hadrons are excitations with respect to the vacuum , hadronic properties are ultimately related to properties of the vacuum . based on the vacuum structure , some hadron properties have been described well . in the low energy region , qcd has two very important proper - ties : chiral symmetry spontaneous breaking and confinement , which are closely related to the vacuum characteristics of qcd . much experiments and theoretical studies have shown that chiral symmetry spontaneous breaking is very important to understand the low - energy feature of the strongly interacting physics , and the quark condensates give an expression to chiral symmetry spontaneous breaking . according to goldstone ' s theorem , the goldstone bosons with zero mass will emerge as the chiral symmetry is spontaneously broken . there are two ways : inear and non - linear methods to carry out this constraint . in our paper , we will use the non - linear method
大量实验和理论研究表明,手征对称自发破缺对于理解低能强相互作用十分重要,而夸克凝聚又是导致手征对称自发破缺的因素。按goldstone理论,伴随手征对称自发破缺应该会有零质量的goldstonebosons产生。而对于这一条件的实现有线性和非线性两种方法本文将用非线性的方法将手征对称自发破缺应用于su ( 3 )模型即重子八重态,得出描述其强相互作用的手征对称自发破缺lagrange密度。
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